How does one calculate the rise time of the ramp-up circuit at PH1 in the attachment? I think the output voltage will be approximately 11.3 V; is that correct? Thanks.
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Oh, about 5 time (R1*C1).How does one calculate the rise time of the ramp-up circuit at PH1 in the attachment? I think the output voltage will be approximately 11.3 V; is that correct? Thanks.
(Vss-Vi)
time = RC * ln ----------
(Vss-Vf)
Where:
RC = Resistance times Capacitance (the 'tau')
Vss = final steady state voltage
Vi = initial voltage on cap
Vf = final voltage on cap
ln = natural log
Oops, my bad. I left out the RC term in that equation. I corrected my post above to reflect that.Thanks for the explanation, however I am missing something. I don't see how the component values in my circuit are taken into account by the equation.
OK, so in my schematic, the time is still 1.223 seconds because 10k times .0001 (100μF) is 1. Correct?When you get that 1.23 seconds, it is actually 1.223*R*C. So you have to include those factors to predict your desired response.
I appreciate you responding to my question, but I wasn't knowledgeable enough to use any of your equations without more explanation.Vo = dV (e^-t/RC)
t = -RC Ln Vo/dV
RC = -t/(Ln Vo/dV)
R = -t/C (Ln Vo/dV)
C = -t/R (Ln Vo/dV)
dV = Vo/(e^-t/RC)
e = 2.71828183
Glad you could use one of these equasions.