# Question in relation to CE amplifier voltage gain.

Discussion in 'General Electronics Chat' started by ECE101, Dec 9, 2011.

1. ### ECE101 Thread Starter New Member

Nov 25, 2011
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Just wondering if anyone could explain the answer to this question?

2. ### thatoneguy AAC Fanatic!

Feb 19, 2009
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Do you have a slightly bigger version of the image?

I'm reading it as the voltage is applied at the output (after the capacitor), is that correct?

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3. ### Audioguru New Member

Dec 20, 2007
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The gm and re of the transistor changes when the transistor's current changes.
When the collector voltage increases because the transistor's current is reducing then the gm is also reducing which reduces the voltage gain.

If the transistor is amplifying a sine-wave then the top portion is compressed and the botton portion is expanded causing severe distortion like this simulation:

• ###### Sim transistor distortion3.PNG
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4. ### ECE101 Thread Starter New Member

Nov 25, 2011
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Vin is to the left, before the input coupling cap C1, V out is to the right after C2.

Ah I understand, thanks for the explanation!

5. ### crutschow Expert

Mar 14, 2008
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The relative effect of the change in re (and gm which is determined by re) with collector current is determined by the value of re as compared to the emitter impedance at the frequency being measured. If the emitter impedance is much larger than re, then the change in re will have little effect on the circuit gain.

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6. ### ECE101 Thread Starter New Member

Nov 25, 2011
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From a mathematical point of view:

Gain = -gm*Rc

gm = Ic1/Vt
Rc = 8k

When Vo = +15

AV = -((15/8*10^3)/25*10-3) * 8*10^3
= -600

When Vo = -10

AV = ((10/8*10^3)/25*10-3) * 8*10^3
= 400

Is this correct?