question in 8086/8088

Discussion in 'Embedded Systems and Microcontrollers' started by Embedded Lover, Jan 8, 2009.

  1. Embedded Lover

    Thread Starter Member

    Dec 22, 2008
    26
    0
    Hello every body , i read this statement which i cant understand ,

    In an 8088/8086 the high addresses in the

    memory map should always be occupied by a

    ROM, while the low addresses in the

    memory map should always be occupied by a

    RAM.

    why ?
     
  2. beenthere

    Retired Moderator

    Apr 20, 2004
    15,815
    282
    It pretty well worked that way for the old 8 bit microprocessors. The power on sequence loads the last 2 bytes of memory (FFFE & FFFF) into the address register as a jump vector. If you don't have ROM present, then nobody's home and the processor won't boot or start the process running.
     
  3. Embedded Lover

    Thread Starter Member

    Dec 22, 2008
    26
    0
    yes got it ,and the 8088 processor start loading at address FFFF0H

    Thanks So much
     
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