Discussion in 'Homework Help' started by mohab1220, Apr 15, 2010.

1. ### mohab1220 Thread Starter New Member

Apr 15, 2010
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how it comes 0.5 A ??

thank you

2. ### Eng_Bandar Active Member

Feb 27, 2010
50
1
The answer is 0.9 A not 0.5 A ( that mean all answers in this question will be wrong )

3. ### mohab1220 Thread Starter New Member

Apr 15, 2010
7
0
how ???????????/!!!! !!!!!!!!!!!!!!!!!

4. ### Eng_Bandar Active Member

Feb 27, 2010
50
1
see the circuit

now calculate I ( total current)
Ra=(6*2)/(6+2)=1.5 Ω ; Rb=(2*2)/(2+2)=1 Ω ; Re=Ra+Rb=2.5 Ω
I=9/2.5=3.6 A

by divider rule
i1=(2/(6+2))*3.6 = 0.9 A
now
V1=i1*6= 0.9*6=5.4 v
V2= 9-V1 = 9-5.4 = 3.6 v
i3=3.6*2=1.8 A

now apply KCL
i1=i3+i0
i0=i1-i3=0.9-1.8=-0.9A
that is mean, direction of i0 must be in opposite direction only but its value 0.9 A

you can also sure from this answer by apply mesh method

5. ### mohab1220 Thread Starter New Member

Apr 15, 2010
7
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i think we use Kirchhoff because the lesson talking about it

Apr 15, 2010
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7. ### mohab1220 Thread Starter New Member

Apr 15, 2010
7
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Last edited: Apr 15, 2010
8. ### mohab1220 Thread Starter New Member

Apr 15, 2010
7
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thank you Eng_Bandar you help me full

Feb 17, 2009
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Apr 15, 2010
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