Then you probably need to go back and read through the basic intro material to digital logic again -- there's probably other things you've missed.no im not sure
Yes.is it inverse?
is this the same as my (AB) bar question?[
Yes.
So, with that in mind, what would
\(
\text{Y \; = \; \bar{\bar{A}}}
\)
be equal to?
Yes, A double bar is just A.is this the same as my (AB) bar question?
that would be A?
y does your have 2 solid bars while mine is 1 solid and 1 split?
NO! The difference is CRITICAL!so then would my (AB) with a solid and split just be AB?
Yes, but what is it you are trying to accomplish?im going to try and attempt my hw problem, i know im just trying random things but I think this would work.
A AND gate gives me AB
A NAND gates gives me AB(bar)
A OR gates gives me (A+B)
so if I have those 3 hooked to a OR gate my output would be AB+AB(bar)+(A+B) right?
View attachment 84090
There are several ways to see how. Let's work through a couple of them.1 gate will give me that solution? how?
Don't forget that a NOT gate can be combined with an AND or an OR to get two new gates....1 gate will give me that solution? how?
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