hi all,
Sorry for mistake at the title. it is a base biasing but not a voltage divider biasing.
Basically i'm trying to understand the operation of a BJT (2N3904). I had tried on plotting out the Ic versus Vce curve. What i get from the plot is that when i fixed Ib= 0.02mA Ic is almost constant when Vce is more than 0.6V. ok this make sense.
Then, i go for base biasing method. Rc i put a 3Kohm and Rb i put a 3.9Kohm resistor. While for Vdd i supply in a 5Vdc. When i tried to measure Id, Ic and Vce i get this results. Ic=1.7mA and Ib=1.10mA and Vce = 0.02V. So it means my BJT is not biased(am i right?). How can i calculate the resistor value to bias 2N3904?
thank you.
Sorry for mistake at the title. it is a base biasing but not a voltage divider biasing.
Basically i'm trying to understand the operation of a BJT (2N3904). I had tried on plotting out the Ic versus Vce curve. What i get from the plot is that when i fixed Ib= 0.02mA Ic is almost constant when Vce is more than 0.6V. ok this make sense.
Then, i go for base biasing method. Rc i put a 3Kohm and Rb i put a 3.9Kohm resistor. While for Vdd i supply in a 5Vdc. When i tried to measure Id, Ic and Vce i get this results. Ic=1.7mA and Ib=1.10mA and Vce = 0.02V. So it means my BJT is not biased(am i right?). How can i calculate the resistor value to bias 2N3904?
thank you.