I don't need them to be worked out,I just want to make sure I understand the process using mesh analysis on these circuits for Voc.
Problem 1) (aka Thev Concept)
To determine Voc:
I1:
9KΩI1=15V
I1=15V/9KΩ -> Voc=6(15V/9KΩ)=0.0017V
I didn't include the Dependent Current Controlled Voltage Source and 4Kohm resistor since it isn't a loop that is closed,and doesn't have any voltage across it b/c im treating A and B as an open circuit?Right?
Problem 2) (aka Thev Concept 2)
To determine the voltage across A and B, for Voc:
I1:
9ΩI1-6ΩI2=16V
I2:
-6ΩI1+12ΩI2=0
I1=4/3A
I2=-4/3A
To determine Voc we subtract the difference of B-A=Voc(a,b)
Voltage at B:
6Ω*(-4/6)=-4 (I added the 4ohm and 2ohm together since there isn't any current through AB wouldn't this mean that the 4 and 2ohm resistors are in series?
Voltage at A:
6Ω(-4/6)=-4
So B-A= -4-(-4)=0 ? Correct?
Problem 1) (aka Thev Concept)
To determine Voc:
I1:
9KΩI1=15V
I1=15V/9KΩ -> Voc=6(15V/9KΩ)=0.0017V
I didn't include the Dependent Current Controlled Voltage Source and 4Kohm resistor since it isn't a loop that is closed,and doesn't have any voltage across it b/c im treating A and B as an open circuit?Right?
Problem 2) (aka Thev Concept 2)
To determine the voltage across A and B, for Voc:
I1:
9ΩI1-6ΩI2=16V
I2:
-6ΩI1+12ΩI2=0
I1=4/3A
I2=-4/3A
To determine Voc we subtract the difference of B-A=Voc(a,b)
Voltage at B:
6Ω*(-4/6)=-4 (I added the 4ohm and 2ohm together since there isn't any current through AB wouldn't this mean that the 4 and 2ohm resistors are in series?
Voltage at A:
6Ω(-4/6)=-4
So B-A= -4-(-4)=0 ? Correct?
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