Im having some trouble in explaining/understanding the "checking your work" after you solve your problem, for real world applications.
I posted the problem below.
Node analysis-Current leaving is positive
V1:
KCL @ V1 = I1+I2+I3=0
((V1-21V)/5Ω)+(V1/10Ω)+((V1-V2)/5Ω)=0
V1(1/5Ω+1/10Ω+1/5Ω)-V2(1/5Ω)=21/5V
V2:
KCL @ V2 = I4+I5+I6=0
((V2-V1)/5Ω))+(V2/10)+((V2+10.5V)/5Ω))=0
-V1(1/5Ω)+V2(1/5Ω+1/10Ω+1/5Ω)=-10.5/5V
I solve for V1 by using the Nodal Equation of V1.
V1=(8.4+V2(0.4)) Then plug this into Node Equation of V2.
V2=-1V Then plug this into V1=(8.4+V2(0.4)) V1=8V
Now to check my work.
I want to test and see if the voltage's that involve the 21V dependent source.Do in fact add up to 21V.
V1+I1(5Ω)=21V
Now do I use my original KCL of V1 which says I1+I2+I3=0 and solve for I1. I1=-I2-I3 Or do I just add up I1=I2+I3 since current leaving must be equal to current entering?
Plugging in with I1=-I2-I3
8V+(-8V/10Ω)-((8+1)/5Ω))=-5V Doesn't equal 21V
But when I just plug in I1=I2+I3 I get 21V
So how do I put this into words? And I just use the Current Continuity which is current leaving=current entering and not my original KCL of V1?
I posted the problem below.
Node analysis-Current leaving is positive
V1:
KCL @ V1 = I1+I2+I3=0
((V1-21V)/5Ω)+(V1/10Ω)+((V1-V2)/5Ω)=0
V1(1/5Ω+1/10Ω+1/5Ω)-V2(1/5Ω)=21/5V
V2:
KCL @ V2 = I4+I5+I6=0
((V2-V1)/5Ω))+(V2/10)+((V2+10.5V)/5Ω))=0
-V1(1/5Ω)+V2(1/5Ω+1/10Ω+1/5Ω)=-10.5/5V
I solve for V1 by using the Nodal Equation of V1.
V1=(8.4+V2(0.4)) Then plug this into Node Equation of V2.
V2=-1V Then plug this into V1=(8.4+V2(0.4)) V1=8V
Now to check my work.
I want to test and see if the voltage's that involve the 21V dependent source.Do in fact add up to 21V.
V1+I1(5Ω)=21V
Now do I use my original KCL of V1 which says I1+I2+I3=0 and solve for I1. I1=-I2-I3 Or do I just add up I1=I2+I3 since current leaving must be equal to current entering?
Plugging in with I1=-I2-I3
8V+(-8V/10Ω)-((8+1)/5Ω))=-5V Doesn't equal 21V
But when I just plug in I1=I2+I3 I get 21V
So how do I put this into words? And I just use the Current Continuity which is current leaving=current entering and not my original KCL of V1?
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