Quantization Gain Problem

Discussion in 'Homework Help' started by k31453, Nov 19, 2013.

  1. k31453

    Thread Starter Member

    May 7, 2013
    54
    0
    Quantization noise power is proportional to d2 / 12 where d is the step size in volts. What will
    be the gain in Signal to Quantization Noise Ratio (SQNR) of going from 4 bit encoding to 8 bit
    encoding? Express your answer in dB.

    I know we have to assume v= voltage range. But then idk what to do ?
     
  2. shteii01

    AAC Fanatic!

    Feb 19, 2010
    3,397
    497
    There are several ways to calculate SQNR.

    In this case you want the formula that relies on bits:
    SQNR in dB=6.02*B dB
    B is number of bits.

    So.
    1) Solve for 4 bits.
    2) Solve for 8 bits.
    3) Find the difference.

    This assumes that the signal is full-scale uniformly distributed random signal.

    This is from my textbook. Software Radio: A Modern Approach to Radio Engineering, Jeffrey H. Reed.
    http://books.google.com/books/about/Software_Radio.html?id=7-XJOmNvAOkC
     
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