Quadratic Equation help?

Discussion in 'Math' started by Khalid Abur-Rahman, Feb 11, 2009.

  1. Khalid Abur-Rahman

    Thread Starter Active Member

    Dec 25, 2008
    34
    0
    Can someone show me how to put this equation into quadratic forum?

    its specifaclly for JFET design by the way (Common Source Amplifier)


    A(v) = -(20k||R(d)/3k-R(d)+350=-4


    where k is for kilo ohms..

    how do I put it in quadratic form?

    Can you show me step by step?
     
  2. studiot

    AAC Fanatic!

    Nov 9, 2007
    5,005
    513
    I am not sure where the -4 comes in, is this the numerical value of the amplifcation?

    \frac{20000*Rd}{20000+Rd} * \frac{-1}{3000-Rd+350}

    If you multiply out the fractions you will get your quadratic in Rd. You should be able to carry on.

    Perhaps if you set this equal to -4 you will be able solve for Rd.
     
  3. nene biggie

    New Member

    Feb 28, 2009
    3
    0
    simplify to the simplest form then amply the quadratic formular ie x=-b+/-√b-4ac all over 2a
     
Loading...