Problems with simple calculation

Discussion in 'Homework Help' started by ihaveaquestion, Mar 24, 2010.

  1. ihaveaquestion

    Thread Starter Active Member

    May 1, 2009
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    0
    http://img269.imageshack.us/img269/1556/32975927.jpg

    I'm interpreting it as saying that you take .15 of the new accumulated value for each increase in a degree C... So Is(total) = Is1 + Is1*.15 + Is2*.15 where Is2=Is1*.15 and do that 100 times... not sure how though.

    Thanks
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    It's simply .....

    Is[@25C]*(1.15)^100 = 10^(-14)*1.174*10^6=1.174*10^(-8)
     
  3. jpanhalt

    AAC Fanatic!

    Jan 18, 2008
    5,692
    901
    You may be missing the simple formula for doing it. You are not trying to calculate the sum of the terms, only the final term. The increase is (1+rate)^n. The final answer is: Is(total) = Is(initial)(1+0.15)^100

    John
     
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