If you want to drive two kinds of LEDs, then you should in parallel the LED at the output of ULN2803 and in series with a resistor for each LED as:Kind of overlooked that. So driving the 2803 in series AFTER the LEDs and grounding them within the 2803?? Or just removing them....
Man, I think you're onto something.
+V → Resistor → Red LED → output1 of ULN2803.
+V → Resistor → Yellow LED → output1 of ULN2803.
ULN2803 can be sink 500mA current, whatever is total or each output, they are the same, but you better only using it less than 1/3 of 500mA that it's about 166mA.