# Problem

Discussion in 'General Electronics Chat' started by Annu007, Nov 16, 2006.

1. ### Annu007 Thread Starter Member

Jun 12, 2006
11
0
Hello,
Can anybody show me how to solve this problem (Value of R2)?

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2. ### kubeek AAC Fanatic!

Sep 20, 2005
4,670
804
Best solution for me is using Kirchhoff´s law:
1) Sum of currents in one joint equals 0
2) Sum of voltages in one loop (don´t know the right term) is equal to zero.

Nov 17, 2003
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4. ### hgmjr Moderator

Jan 28, 2005
9,030
214
Once you have reviewed the material contained in the link that Dave has posted, then give the calculation a whirl and then post your calculations and your results. We will be happy to provide you a bit of guidance if needed.

hgmjr

5. ### Annu007 Thread Starter Member

Jun 12, 2006
11
0
I came up with 13K for R2.
Vo = 0.25ma * 5K +0.7V
Vo = 1.95V
I1= I2 + ID
I1 = 12V/30K =0.4mA
ID = 0.25mA (Given)
I2 = 0.4-0.25 =0.15mA
V0 = 1.95V
R2 = 1.95V/0.15mA = 13K

6. ### richbrune Senior Member

Oct 28, 2005
106
0
The part about 12v/30k doesn't look right; the voltage drop across the 30k can't be all of the 12v, it's got to be something less than that, seems like about 9 or 10 volts, because you've got to subtract the voltage drops caused by all of the 3 remaining components. I got 40678, but I don't have time to check it before I leave---Sorry, Rich

7. ### Annu007 Thread Starter Member

Jun 12, 2006
11
0
Vo = 12-1.95 = 10.05V

I1 = 10.05/30K = .335mA

I2 = 0.335-.25 = .85mA

R2 = 1.95/0.85 = 22.94K

8. ### Syed New Member

Dec 5, 2005
6
0
Right..... except 0.335-0.25=0.085 and 1.95/0.85=2.2941 so 1.95/0.085=22.941

Jan 28, 2005
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