Problem in Finding Answer

Discussion in 'Homework Help' started by Ambitious_Probe, Feb 22, 2016.

  1. Ambitious_Probe

    Thread Starter New Member

    Feb 7, 2016
    2
    0
    Alexander_pp_3.13_pg#110.JPG
    Using KVL as
    -1 + (30K Ohm)(IB)+0.7=0
    Base Current is found to be IB= 800uA,
    I am confused how to find Vo and Io , please describe mathematically.
     
  2. MrAl

    Well-Known Member

    Jun 17, 2014
    2,431
    490
    Hi,

    Problem with your "30K", it is a 300k resistor.

    Start by calculating the base current as you did but using the right resistor value, unless of course you intended to use a different value for that resistor.
    Multiply by the Beta to get the collector current Ic, which is directed downward.
    Use Thevenin and/or Norton to convert the battery and 20k to a current source in parallel with the 20k, we'll call it Ix.
    The current through the two now parallel resistors is Ip=Ix+Ic, and remember Ic will be negative or simply subtracted from Ip as: Ip=Ix-Ic.
    Multiply Ip times the parallel resistance of the 20k and 200k to obtain Vo.
    Check to see that the solution voltage is actually possible with a 10v battery.
     
    Last edited: Feb 22, 2016
  3. Bordodynov

    Active Member

    May 20, 2015
    637
    188
    -1 + (300KOhm)(IB)+0.7=0 ==> (300KOhm)(IB)=1-0.7=300mV

    SC0.png
     
    Last edited: Feb 24, 2016
    MrAl likes this.
  4. shteii01

    AAC Fanatic!

    Feb 19, 2010
    3,388
    497
    You have two loops there.
    You only did one loop. The easy one.
    Now do the other loop.
     
  5. WBahn

    Moderator

    Mar 31, 2012
    17,743
    4,792
    Show your work for how you came up with Ib = 800 uA.

    That's not correct, but we can't begin to tell you what you did wrong unless you show us what you did, period.
     
  6. MrAl

    Well-Known Member

    Jun 17, 2014
    2,431
    490
    Hi,

    Nice diagram by Bordodynov in post #3. That illustrates the electrotopological transformation to simplify the problem nicely i think. Unfortunately it looks like the OP may not be returning or is taking a long time to reply.
     
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