KaguraHime
- Joined Sep 25, 2013
- 7
Ah, I see the LED now. Sorry for the confusion.
Yes, I do realize:
V=IR
and if R=0
I=V/0=infinity current
The picture of the relay was randomly picked from my schematic drawing lib file and I actually used a different relay for my project, the picture of it wasn't in the lib hence the substitution in the first place. Pardon me.
I was a bit confused when you started talking about an LED. I didn't realize you were talking about the LED "inside" the relay.
The wire connected the transistor's emitter was supposed to go to the relay's coil, which goes to gnd. And I used the relay as a load so I didn't need a resistor.
The LED, which I mistook for a plain diode, actually, was supposed to be connected parallel to the relay to prevent backward current, and not an opto isolator as in the diagram.
And as for the R3 pot, the OP could connect her sensor's positive side to pin 5 of the comparator, and the negative side to gnd. So... we could modify that circuit to get 2 terminals instead of 3.
Thanks for spotting my error, guys.
I'll second #12's suggestion, though.
Yes, I do realize:
V=IR
and if R=0
I=V/0=infinity current
The picture of the relay was randomly picked from my schematic drawing lib file and I actually used a different relay for my project, the picture of it wasn't in the lib hence the substitution in the first place. Pardon me.
I was a bit confused when you started talking about an LED. I didn't realize you were talking about the LED "inside" the relay.
The wire connected the transistor's emitter was supposed to go to the relay's coil, which goes to gnd. And I used the relay as a load so I didn't need a resistor.
The LED, which I mistook for a plain diode, actually, was supposed to be connected parallel to the relay to prevent backward current, and not an opto isolator as in the diagram.
And as for the R3 pot, the OP could connect her sensor's positive side to pin 5 of the comparator, and the negative side to gnd. So... we could modify that circuit to get 2 terminals instead of 3.
Thanks for spotting my error, guys.
I'll second #12's suggestion, though.
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