Power of x(t) = sum of powers of even/odd components

Discussion in 'Homework Help' started by mesaman000, Jan 20, 2011.

  1. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    So I have a question..

    I'm given an analog signal x(t) that just shows the graph x(t)= 1-t from 0 to 1

    It just gives that one line and doesn't say anything about anything past t>1 and t<0 so I guess it's just assumed that its 0 everywhere else

    They want me to plot the even/odd composition and show that the energy of the signal can be expressed as the sum of the energies of the even and odd components.

    So basically i have to prove the following:

    [​IMG]

    I got xe(t)= 1
    xo(t)= -t I KNOW these are right because when you add them you get x(t) and xe(t) is reflective about the y axis and xo(t) is reflective across y=-x

    since the formulas I used were:

    xe(t)= .5[x(t)+x(-t)]
    xo(t)= .5[x(t)-x(-t)]

    When I integrate the values in the integrals in the picture above from 0 to 1, I don't get both sides to equal. Can someone tell me where I'm going wrong please? Thanks a lot!
     
    Last edited: Jan 20, 2011
  2. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    anyone?? please i need help! :(
     
  3. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    nvm i figured it out. THANKS!
     
  4. thatoneguy

    AAC Fanatic!

    Feb 19, 2009
    6,357
    718
    When you have the answer, please post it here so others can learn from what you've posted, and save some the problem of a search.

    No offense, but I can barely read your graphic. ;)
     
Loading...