Power gain

Discussion in 'Homework Help' started by tjjam2003, Apr 18, 2006.

  1. tjjam2003

    Thread Starter Member

    Apr 5, 2006
    22
    0
    An amplifier has a decibel power gain of 32dB. What is the ordinary power gain?

    Now if dB= 10 log P out / P in

    How do I rewrite thew formula to find the ANSWER of 1584.89???
     
  2. pebe

    AAC Fanatic!

    Oct 11, 2004
    628
    3
    10 * log P out / P in =32
    So log P out / P in = 3.2

    Get antilog of 3.2. On my calculator that's
    Shift > Log > 3.2 = 1584.893192
     
  3. Papabravo

    Expert

    Feb 24, 2006
    10,152
    1,794
    On the off chance that you might not know what an antilog is. It is the same as raising 10, the base of common logarithms, to the power of the argument. In symbols:
    Code ( (Unknown Language)):
    1.  
    2. antilog(3.2) = 10 ^ 3.2
    3.  
    If you already knew this, then I apologize for being presumptuous.
     
  4. tjjam2003

    Thread Starter Member

    Apr 5, 2006
    22
    0
    Thank you very much...BIG HELP !!


     
  5. rodn.m

    Member

    May 3, 2006
    12
    0
    thanks

    on my casio fx-100 c calculator

    to get antilog of 3.2

    302>shift>log?1584.893
     
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