# Power gain

Discussion in 'Homework Help' started by tjjam2003, Apr 18, 2006.

1. ### tjjam2003 Thread Starter Member

Apr 5, 2006
22
0
An amplifier has a decibel power gain of 32dB. What is the ordinary power gain?

Now if dB= 10 log P out / P in

How do I rewrite thew formula to find the ANSWER of 1584.89???

2. ### pebe AAC Fanatic!

Oct 11, 2004
628
3
10 * log P out / P in =32
So log P out / P in = 3.2

Get antilog of 3.2. On my calculator that's
Shift > Log > 3.2 = 1584.893192

3. ### Papabravo Expert

Feb 24, 2006
10,340
1,850
On the off chance that you might not know what an antilog is. It is the same as raising 10, the base of common logarithms, to the power of the argument. In symbols:
Code ( (Unknown Language)):
1.
2. antilog(3.2) = 10 ^ 3.2
3.
If you already knew this, then I apologize for being presumptuous.

4. ### tjjam2003 Thread Starter Member

Apr 5, 2006
22
0
Thank you very much...BIG HELP !!

5. ### rodn.m Member

May 3, 2006
12
0
thanks

on my casio fx-100 c calculator

to get antilog of 3.2

302>shift>log?1584.893