power equation

Discussion in 'Homework Help' started by 0001T, Sep 24, 2007.

  1. 0001T

    Thread Starter Member

    Feb 28, 2007
    15
    0
    Hi,

    I am doing a project to measure power required to heat up a wire. I will be measuring the resistance and voltage across the wire against time. Therefore I will have:

    resistance of wire = R(t)
    voltage across wire = V(t)

    I know power =V*R

    So am I correct to do integrate V(t)*R(t) from t=0 to t=t1?

    Thank you.
     
  2. arthur92710

    Active Member

    Jun 25, 2007
    307
    1
    Im not sure about the rest but "I know power =V*R" is wrong
    Power = I*V Current times voltage
     
  3. 0001T

    Thread Starter Member

    Feb 28, 2007
    15
    0
    thanks for the correction. u r right.

    so now my equation will be to integrate V(t)*V(t)/R(t) from t-0 to t-t1.
     
  4. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    I believe you will find that power is actually V squared divided by R.

    hgmjr
     
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