Power Dissipation Of A Coil

Discussion in 'Homework Help' started by Three Phase, Jul 14, 2007.

  1. Three Phase

    Thread Starter Member

    Jul 11, 2007
    13
    0
    A series circuit consists of a coil and a capacitor connected to a 60Hz supply. The circuit has the following values:

    -Coil resistance is 40 ohms.
    -Inductance of the coil is 0.46 henrys.
    -The capacitor is 22 microfarads.
    -The voltage drop across the capacitor is 135 volts.

    What is the power dissipation of the coil?
    Answer - 50.2 Watts.

    What calculations are needed to arrive at that answer?
     
  2. recca02

    Senior Member

    Apr 2, 2007
    1,211
    0
    voltage across capacitor is current*reactance
    135=Xc*I
    ,current in series remains same
    so this current is the same as current thru resistance of the coil.
    power = I^2*R.
    got it?
    u can play with this example by finding various thins like voltage across inductance,
    net impedance of rlc cicuit, current =v/z they all lead to same result and its lot of fun and help in learning.
     
  3. Three Phase

    Thread Starter Member

    Jul 11, 2007
    13
    0
    I got it! Thanks again.:)
     
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