power dissipated on capacitor

Discussion in 'General Electronics Chat' started by luma, Feb 10, 2016.

  1. luma

    Thread Starter Member

    Nov 5, 2015
    48
    0
    Good morning to everyone, I would like to know how did they calculate the power consumed by the supply voltage in this document.
    I mean I don't understand how this formulas come out. Thanks.
     
  2. crutschow

    Expert

    Mar 14, 2008
    13,009
    3,233
    You just need to go through the formulas for the fundamental relationships:

    The charge transferred in and out of the capacitor is Q = C*Vpp
    Since the capacitor is being charged and discharged each cycle, the current drawn from the source is then
    I = f*Q
    (current is charge transferred per second).
    Substituting gives
    I = f*C*Vpp
    The power drawn from the supply is
    P = Vb * I
    Substituting gives
    P = Vb*f*C*Vpp
    (Q.E.D.)
     
    luma likes this.
  3. luma

    Thread Starter Member

    Nov 5, 2015
    48
    0
    thank you very much ...for your answer.
     
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