Power Consumption Math

Discussion in 'General Electronics Chat' started by 7anoter4, Nov 11, 2013.

  1. 7anoter4

    Thread Starter New Member

    Nov 11, 2013
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    Moderator edit: This was split from total power consumption

    If the actual diagram would be Rtot=R1+R2||R3 =R1+R2*R3/(R2+R3)=543.46 ohm then the power consumption will be 450^2/543.46=372.62 w only.You have to supply 459.67 V in order to get 388.8 w.
     
    Last edited by a moderator: Nov 11, 2013
  2. WBahn

    Moderator

    Mar 31, 2012
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    Redo your math. Since you didn't show the details of how you arrived at 543.46Ω, we can't even guess where you might have gone wrong.
     
  3. Wendy

    Moderator

    Mar 24, 2008
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    We don't allow hijacking (taking over someone elses thread) at AAC, so now you have one of your own.

    As I mentioned in the other thread, schematics are the language of electronics. Without a schematic, there is no way to match your math to the problem.

    I explain how to attach a schematic in the other thread.
     
  4. WBahn

    Moderator

    Mar 31, 2012
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    I don't know that this was really a hijacking as opposed to someone just saying that they are not getting the same answer to the same problem. But since I think the OP is probably taken care of, it is not unreasonable to split it off, either.
     
  5. MikeML

    AAC Fanatic!

    Oct 2, 2009
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    The LTSpice sim and schematic I posted way back in post #4 of the original Math thread had the circuit topology right because it did indeed dissipate 388.8W with 450V applied.
     
  6. 7anoter4

    Thread Starter New Member

    Nov 11, 2013
    3
    0
    If the actual diagram would be Rtot=R1+R2||R3 =R1+R2*R3/(R2+R3)=543.46 ohm then the power consumption will be 450^2/543.46=372.62 w only.You have to supply 459.67 V in order to get 388.8 w.You may, also reduce the R3 resistance from 470 to 417.4 ohm to get the same.
     
  7. WBahn

    Moderator

    Mar 31, 2012
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    At the risk of repeating myself.

    Again. Check your math on that equivalent resistance.

    Again. Show your math on that equivalent resistance.

    Again. Your result for the equivalent resistance is wrong.

    Again. We can't point out where you went wrong unless you show your work.

    For instance, just by saying that you can reduce R3 from 470Ω to something else gives a pretty big hint as to what your problem is since R3 isn't 470Ω to begin with.

    SHOW YOUR WORK!!!!!
     
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