Hi everyone,
I have run into an issue during my exam study. I do believe I understand some of the concept but not all of it. For Part (a), I can see that the peak current through the triac is going to be:
\((V_p - V_{triac})/R_2\)
as the current will no longer flow through R1.
However I am unsure as to how to calculate the power. The solution states that the average current is given by:
\(I_{peak} /2{Pi}\)
but i am unsure how this is arrived at. It goes on to say that the power is given by:
\(2 * I_{average} * V_{traic}\)
Why is the power multiplied by 2? Is it due to the sinusoidal input?
I would really appreciate some clarification as to the how the average current and power is calculated. I do apologize if this is a simple question, this topic was barley covered during lectures so my knowledge is a little shaky. Thanks in advance for you help!
Part (b) is not an issue, so no need to look at that.
I have run into an issue during my exam study. I do believe I understand some of the concept but not all of it. For Part (a), I can see that the peak current through the triac is going to be:
\((V_p - V_{triac})/R_2\)
as the current will no longer flow through R1.
However I am unsure as to how to calculate the power. The solution states that the average current is given by:
\(I_{peak} /2{Pi}\)
but i am unsure how this is arrived at. It goes on to say that the power is given by:
\(2 * I_{average} * V_{traic}\)
Why is the power multiplied by 2? Is it due to the sinusoidal input?
I would really appreciate some clarification as to the how the average current and power is calculated. I do apologize if this is a simple question, this topic was barley covered during lectures so my knowledge is a little shaky. Thanks in advance for you help!
Part (b) is not an issue, so no need to look at that.
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