polar rectangular conversions

Discussion in 'Math' started by gcp, Jan 25, 2009.

  1. gcp

    Thread Starter New Member

    Jan 25, 2009
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    Im trying to revive my memory, its been awhile since I had to work with polar and rectangular. I want to add -1@210 deg plus 0@210deg. I converted to rectang and got .866+j.5. when going back to polar I end up with 5@30deg? What am I missing here? I was doing fine working nums up thru 180deg, but after that I am missing something here.
     
  2. hgmjr

    Moderator

    Jan 28, 2005
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    I think you should have gotten the answer 1@30. The sign of the magnitude has changed from negative to positive and the angle has been decreased by 180 degrees. The change in angle offsets the change in sign.

    -1@210 equals 1@30

    hgmjr
     
  3. gcp

    Thread Starter New Member

    Jan 25, 2009
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    Your right on it being 1@30, I typed the wrong number. Now how do I get from that 1@30 to knowing it should read -1@210?
     
  4. hgmjr

    Moderator

    Jan 28, 2005
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    1@30 is equivalent to -1@210. Adding 180 degrees to the angular component of the polar coordinates is the same as multiplying the magnitude by -1.

    hgmjr
     
  5. gcp

    Thread Starter New Member

    Jan 25, 2009
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    Thanks for the help...I thought adding 180 back in had something to do there but I couldnt remember gettting the 1 to neg 1. Heres another that has me stumped. Im adding -.68@200and .69@200 I get 0@0? why the )deg?
     
  6. gcp

    Thread Starter New Member

    Jan 25, 2009
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    make that a 0deg
     
  7. hgmjr

    Moderator

    Jan 28, 2005
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    What do you mean by ")deg"?

    hgmjr
     
  8. gcp

    Thread Starter New Member

    Jan 25, 2009
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    Thats suppose to say 0 @ zero deg. My keyboard doesnt type what i want it to...lol
     
  9. hgmjr

    Moderator

    Jan 28, 2005
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    I suspect that the reason you get 0 degrees is due to round-off error.

    hgmjr
     
  10. gcp

    Thread Starter New Member

    Jan 25, 2009
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    Thanks again..now back to the grind.
     
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