See figure attached for problem statement.

We've been studying RC, LC and RLC circuits in class, but never have we discussed "resonance", or plotting things such as input impedance versus frequency, hence my confusion.

I don't have matlab or anything so I've be trying to plot the following on wolframalpha,

"plot y = log( |100+1/(2200*10^{-12}x)+(10*10^{-3})x| )"

Can someone confirm that this is indeed what I want to plot?

I simply plugged in the values for R, L and C given into our equation for Zin.

It says to use the logarthimic unit for impedance but I'm not entirely sure how to do that.

If that equation is indeed what I am being asked to plot could anyone be so kind as to post a matlab graph? I don't know why they ask for it using matlab, the students were not provided with it nor do we have any access to it.

Is there any other tools out there that I can use to graph this?

Thanks again!

 

The instructions say you can plot the graph manually,

The Log statement involves the graph type, e.g. 1, 10, 100, 1000 isntead of 1,2,3,4, 5

Plug in the numbers given, and calculate the impedance for 20 Hz, 60 Hz, 400Hz, 1khz, 2kHz, 4kHz, 8kHz, etc.

A programmable calculator (HP or TI) will be able to run that equation for different inputs quite readily.

 

The instructions say you can plot the graph manually,

The Log statement involves the graph type, e.g. 1, 10, 100, 1000 isntead of 1,2,3,4, 5

Plug in the numbers given, and calculate the impedance for 20 Hz, 60 Hz, 400Hz, 1khz, 2kHz, 4kHz, 8kHz, etc.

A programmable calculator (HP or TI) will be able to run that equation for different inputs quite readily.

Okay, I've been plotting

y =| 100+1/(2200*10^{-12}x)+(10*10^{-3})x |

In my TI-83 Plus graphing calculator but I can't get the y axis to jump by powers of 10.

Is there a way I can do that on my calculator?

EDIT: See figure attached for my graph. Does this look correct? I still can't get it to plot the y axis high enough to see the resonant frequency

 

Is there any other tools out there that I can use to graph this?

Thanks again!

Maxima is free and can plot mathematical functions:

http://maxima.sourceforge.net/

 

Graph doesn't look right, capacitor and inductor in series make a bandpass filter, so it should be a "U" shaped graph. The graph above appears to only calculate the capacitance portion of the impedance. Equation using f for frequency (remember multiply by 2pi) -> R+j(L*f-1/C*f)

MiscEl (freeware) gave me this info on the LCRs series circuit with 100 Ohm output Z

Fo: 33.9319 kHz
Zin min: 200.001 ohm
Zout min: 50.0002 ohm
Zout max: 100 ohm

Bandwidth:
Passband gain: -6.02 dB (500m) at Fo
-18 dB low freq.: 28.35 kHz
-18 dB high freq.: 40.61 kHz
-18 dB bandwidth: 12.27 kHz

Small signal analysis

At: 10 Hz
Gain: -97.2 dB (13.8µ)
Phase: 90 °
Zin: 7.23 Mohm
Zout: 100 ohm

At: 100 Hz
Gain: -77.2 dB (138µ)
Phase: 90 °
Zin: 723 kohm
Zout: 100 ohm

At: 1 kHz
Gain: -57.2 dB (1.38m)
Phase: 89.8 °
Zin: 72.3 kohm
Zout: 100 ohm

At: 100 kHz
Gain: -34.9 dB (18m)
Phase: -87.9 °
Zin: 5.56 kohm
Zout: 100 ohm

At: 1 MHz
Gain: -56 dB (1.59m)
Phase: -89.8 °
Zin: 62.8 kohm
Zout: 100 ohm

 

Don't ignore the advice in your problem that says "Note that the values are complex..."

You should get a plot like the one shown in the attachment.

 

Don't ignore the advice in your problem that says "Note that the values are complex..."

You should get a plot like the one shown in the attachment.

So is the dip in the middle of the graph going to be my resonance frequency?

 

So is the dip in the middle of the graph going to be my resonance frequency?

Yes, the point where inductive impedance and capacitive impedance match.

 

Yes, the point where inductive impedance and capacitive impedance match.

I've calculated the resonance frequency to be 33931.95 Hz, is this correct? It seems to agree with the graph as well.

Also, how do I calculate half power bandwidth?

The only formula I'm given is,

\(\beta = \omega_{H} - \omega_{L}\)

Where \(\omega_{H},\omega_{L} \) are the frequencies that correspond to \(\frac{1}{sqrt{2}}\) times the maximum voltage value.

But we don't have any voltage values, so how do we find it?

Thanks again!

 

Fo is correct.

Here is a link to a page describing the 3dB down point (half power) with formulas and a graph to get the idea of what the bandwidth is between the two -3dB points.

 

I've been trying to make the graphs on maxima, but I can't figure it out. Can you tell me what steps you did to get that graph?

I want it to only have a log scale on the Y axis and not such a large range on the x axis.

Help?