Please Help :(

Discussion in 'Math' started by Girlzone, Apr 5, 2004.

  1. Girlzone

    Thread Starter New Member

    Apr 5, 2004
    1
    0
    Hi all,
    i have a question, which ask to prove the identity of the following Boolean equation, using algebraic manipulation:

    XZ + WY'Z' + W'YZ' + WX'Z' = XZ + WY'Z' + WXY' + W'XY + X'YZ'

    i have tried many times to solve it but its very hard :wacko: , would please any one help me with it ..
    Thanx a lot
     
  2. m4yh3m

    Senior Member

    Apr 28, 2004
    186
    42
    I just joined here... but I figured I'd give a response anyways in case if others were curious.

    Problem:
    XZ+WY'Z'+W'YZ'+WX'Z'=XZ+WY'Z'+WXY'+W'XY+X'YZ'

    Solution:
    First, convert those ugly end of the alphabet letters to the more frequently used letters... A through H.
    A=W
    B=X
    C=Y
    D=Z

    Our new problem looks like this:
    BD+AC'D'+A'CD'+AB'D'=BD+AC'D'+ABC'+A'BC+B'CD'

    Now simplify both sides to get:
    A'CD'+AB'D'+AC'D'+BD=A'CD'+AB'D'+AC'D'+BD
     
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