Discussion in 'General Electronics Chat' started by shebby, May 22, 2013.

1. ### shebby Thread Starter New Member

May 21, 2013
3
0
I am a high school student struggling with series parallel circuits please help with this question and explain how to break down. I will try my best to show problem

Code ( (Unknown Language)):
1.
2. [FONT=Calibri][SIZE=3] [SIZE=1]------------------------------------ [SIZE=3]v[/SIZE]------------------[/SIZE][SIZE=1]3o 0hm-----------------------------------------------------------[/SIZE]v[/SIZE][/FONT]
3. [FONT=Calibri][SIZE=3]                               [SIZE=1]10 ohm[/SIZE]                                                    [/SIZE][SIZE=1]1[/SIZE][SIZE=1]0 watt 120 volt lamp[/SIZE][/FONT]
4. [FONT=Calibri][SIZE=3]                                [SIZE=1]10 ohm[/SIZE]                                                              v[/SIZE][/FONT]
5. [FONT=Calibri][SIZE=3]   ---------------------------------------------------------------------- <[/SIZE][/FONT]
6. [FONT=Calibri][SIZE=3] [SIZE=2]
7. [/SIZE][/SIZE][/FONT]
sorry bad diagram but cant copy paste. this is a circuit the v indicates arrows continuing the circuit. 1 branch has 2 10 ohm resistors. the other main circuit has a 30 ohm resistor and a 10 watt 120volt lamp. Please help answer. im pretty sure the formula is 1 over, 1 over R1 + 1 over R2 + 1 over R3 but im lost for some reason.
Question.
When current is flowing through the 10-ohm resistors, the voltmeter reading will besince its hard to show the volt meter is placed across the bottom 10 ohm resistor).

Last edited by a moderator: May 24, 2013
2. ### shebby Thread Starter New Member

May 21, 2013
3
0
thw 10 watt 120 volt lamp should be in the rear between arrows. this circuit is 120 volts

3. ### shebby Thread Starter New Member

May 21, 2013
3
0
the 10 watt 120 volt lamp should be in rear of circuit between arrows, circuit is 120 volts

4. ### davebee Well-Known Member

Oct 22, 2008
539
46
If I could understand the circuit I would try to help but the description of the circuit is not clear enough and the picture is too messed up.