A Thevenin voltage generator consists of an ideal voltage source V(t) (given) in electrical series with an RL series combination (given R,L).a variable resistor is connected across this generator. if we adjust the the RL so that it dissipates maximum power what is the power dissipated by RL.
the voltage will be in the form Vmaxsin(wt).
can someone please check my work to see if it all checks out its really important i do well on this.
so i know that for maximum power transfer the Zth has to be equal to the Zload
here i know that Zth will be sqrt(R^2 +(w^2)(L^2) which is equal to Zload
so then Zload must be equal to Rload
the current going through the circuit will be
I = (Vmax/Zth + Zload)
and P = (Irms^2)(Rload) = (Rload/2)(Vmax/(Zth+Zload))^2
if this is not correct please any hints towards the answer would be appreciated
the voltage will be in the form Vmaxsin(wt).
can someone please check my work to see if it all checks out its really important i do well on this.
so i know that for maximum power transfer the Zth has to be equal to the Zload
here i know that Zth will be sqrt(R^2 +(w^2)(L^2) which is equal to Zload
so then Zload must be equal to Rload
the current going through the circuit will be
I = (Vmax/Zth + Zload)
and P = (Irms^2)(Rload) = (Rload/2)(Vmax/(Zth+Zload))^2
if this is not correct please any hints towards the answer would be appreciated