Physics question. (a BALL)

Discussion in 'Physics' started by redlight000, Mar 22, 2010.

  1. redlight000

    Thread Starter Member

    Feb 26, 2010
    66
    2

    If a ball is thown upwards with a velocity of 75 feet per second, what is its velocity at the end of 1.6 seconds??

    In my calculator sheet) here's the data:

    (g=32.2 ft/sec2)?
    Velocity V = Vo - gl
    = 75 - (32.2 x 16)
    = 23.48 ft/sec.
    Height S = Vol - 1/2 gl2 = (75x1.6)-(1/2 x 32.2 x (1.6)squared2)
    = ?
    thanks
    redlight000
    :)
     
  2. rjenkins

    AAC Fanatic!

    Nov 6, 2005
    1,015
    69
    The velocity should be just 75 - (32.2 * 1.6) = 23.48

    The distance travelled would be the mean of that velocity * 1.6 so
    Mean of 75 & 23.48 = 49.24, * 1.6 = 78.784

    That's how I would work it out, I hope it's correct..
     
  3. someonesdad

    Senior Member

    Jul 7, 2009
    1,585
    141
    This is a constant acceleration problem, so the usual kinematic equations apply. The key is to recognize that you know: the initial velocity, the acceleration (note it's negative), and the time. Distance as a function of time is a quadratic in time, so it's just plug and chug.
     
  4. redlight000

    Thread Starter Member

    Feb 26, 2010
    66
    2
    Hi Rjenkins,

    well done Spot on.. congrats
    :D
     
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