Phasors and Nodal Analysis

Discussion in 'Homework Help' started by KTD108, Oct 1, 2008.

  1. KTD108

    Thread Starter New Member

    Sep 14, 2008
    I have a circuit for my homework and we are supposed to use Mesh Analysis. I have figured out the following equations: I1 and I2 are the mesh currents. Also note than 10<0 means 10 angle 0 degrees.

    5(I1) + j5(I2) + 10(I2) = 10<0
    I1 - I2 = 2<0

    For the first equation, I reduced it to the following by substituting in (-2<0 + I1) for I2...deduced from the 2nd equation above:

    5(I1) + j5(-2<0 + I1) + 10(-2<0 + I1) = 10<0

    I know in order to do addition and subtraction it must be in complex form (x+jy), and I know in order to multiply and divide it must be in phasor form #<theta. So I was going to convert the -2<0 to complex form so that it was just -2, but then I wasn't sure how to simplify j5 (-2 + I1) or the rest of the equation for that matter.

    Any help would be much appreciated!
  2. mik3

    Senior Member

    Feb 4, 2008
    say you have this


    to convert it to polar form (phasor):



    and you get P<a

    If you have P<a, to convert it to rectangular form (complex):


    and you get A+jB