# phasor rectangular to polar

Discussion in 'General Electronics Chat' started by Asad ahmed1, Mar 2, 2016.

Feb 10, 2016
68
0
its in the 4th quadrant so can i separate the angle form 2pi ? from the last I equation

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2. ### Papabravo Expert

Feb 24, 2006
10,145
1,791
-110° is not in the 4th quadrant, it is in the third, but that is irrelevant. What is relevant is that the process requires you to convert from polar to rectangular, do the addition, and then convert back to polar. You cannot do addition and subtraction of phasors in polar form. You can do multiplication and division of phasors in polar form. Do you agree with that?

Feb 10, 2016
68
0
yes I do but i want to ask that the arctan-2.698\1.754

1. IF x > 0 // Quadrants I and IV
2. angle = atan(y/x)
3. ELSE
4. IF y > 0 // Quadrant II
5. angle = atan(y/x) + 180°
7. angle = atan(y/x) - 180
why we left 4th quadrant why not 2pi-theta

4. ### StayatHomeElectronics Well-Known Member

Sep 25, 2008
864
40
the atan() function will give you the correct results if you are in quadrants I and IV. If you are in quadrant I the angle will be positive. If you are in quadrant IV the angle will be negative. There is no need to adjust the result of the equation on line 3.

A positive angle is a counter-clockwise rotation from the positive x-axis. A negative angle is just a clockwise rotation from the positive x-axis. We can convert between the two by either adding or subtracting 360 degrees from our angles.

5. ### StayatHomeElectronics Well-Known Member

Sep 25, 2008
864
40
The angle on the final line of your initial file, -57 degrees, is in the 4th quadrant.