So I'm trying to work my way through some of the exercises in my ac course, but I just can't seem to make it make sense. Anyhow, I was hoping someone would be able to help me out with it.
The example I'm given, and I'm quoting from this (terrible) textbook:
*note that section 14.10 says nothing about adding vectors in polar form, and everything I've seen seems to indicate that it's impossible unless the angles are multiples of 180°.
The example I'm given, and I'm quoting from this (terrible) textbook:
Anyhow, the entire book reads like it was written from one engineer to another engineer, rather than to a student, but I won't get into that too much. I'm just trying to figure out what the heck they're doing and how it's supposed to work to add phasors together.Introductory Circuit Analysis said:It can be shown using the vector algebra described in section 14.10* that 1V\(\angle\)0° + 2V\(\angle\)90° = 2.236V\(\angle\)63.43°.
In other words, if we convert v\(_{1}\) and v\(_{2}\) to phasor form using
v = V\(_{m}\)sin(ωt ± θ) \(\Rightarrow\) V\(_{m}\)\(\angle\)±θ
and add them using complex number algebra, we can find the phasor form for V\(_{T}\) with very little difficulty.
*note that section 14.10 says nothing about adding vectors in polar form, and everything I've seen seems to indicate that it's impossible unless the angles are multiples of 180°.