oscillator in microcontroller

Discussion in 'Embedded Systems and Microcontrollers' started by bhuvanesh, Dec 23, 2013.

  1. bhuvanesh

    Thread Starter Member

    Aug 10, 2013
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    if we see in arduino we have crystal oscillator in its board.it produce square wave of frequency about 16 mhz or something else.My question is how it would be related to input.explain me basically with some examples.thank you in advance
     
  2. tubeguy

    Well-Known Member

    Nov 3, 2012
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    I'll start.

    The crystals frequency determines the speed at which the Arduino executes instructions.
     
  3. bhuvanesh

    Thread Starter Member

    Aug 10, 2013
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    this is what i exactly mean if we write a code to off some thing after 5 seconds.it will calculate time from oscillator.it off after16mhz*5 cycles am i right.please someone come forward.i am in little choas
     
  4. shteii01

    AAC Fanatic!

    Feb 19, 2010
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    I would start with datasheet.
     
  5. atferrari

    AAC Fanatic!

    Jan 6, 2004
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    Those generic questions are better served reading the basics of digital techniques. While a datasheet is not going to mention all the basics, google for it and then read a datasheet to complement.
     
  6. MrChips

    Moderator

    Oct 2, 2009
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    An alternative is to tell us what you don't understand and we will attempt to explain it for you.
     
  7. BillB3857

    Senior Member

    Feb 28, 2009
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    As an example, when you tell the Arduino by code to delay(1000);, the compiler lets the guts of the chip know to count 16 million clock cycles while doing nothing else.
     
  8. tshuck

    Well-Known Member

    Oct 18, 2012
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    It is also important to note that these are machine instruction (think assembly programming) times, not instructions done in Processing.
     
  9. Brownout

    Well-Known Member

    Jan 10, 2012
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    Typically, there are some numbers of clock cycles per delay. So, for example, if you want to delay 5ms, your clock is 16mhz and there are 4 clock periods per delay count:

    delay = count*clock_per_count*clock_period

    substituting some numbers:

    5ms = count*4*(1/16e6) or count = 5ms*16e6/4 = 20,000.
     
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