Still having fun here...follow the bouncing ball...
abc = (ab)c = a(bc)
Right? Now, your saying that division is just the same as multiplication right? So we can go ahead and write:
a/bc = (a/b)c = a/(bc) ... ooops, problem here. Still with me?
(a/b)c is not = a/(bc)
Are you guy's forgetting that multiplication is associative and division is not? You cannot just toss divisive factors around like multiplicative factors
So, when you mean c*a/b, you do not write it a/bc, or even a/b*c.
c*a/b is invariant under association. No ambiguity. a/bc is not.
a/bc or 48/2(9+3) are just <snip>. Nothing more.
To this point, which is correct, given three factor a, b, c we can therefore write:Ok. I'm gonna stir this up.
2. and the Commutative Rule says: "The order of factors does not matter".
abc = (ab)c = a(bc)
Right? Now, your saying that division is just the same as multiplication right? So we can go ahead and write:
a/bc = (a/b)c = a/(bc) ... ooops, problem here. Still with me?
(a/b)c is not = a/(bc)
Are you guy's forgetting that multiplication is associative and division is not? You cannot just toss divisive factors around like multiplicative factors
So, when you mean c*a/b, you do not write it a/bc, or even a/b*c.
c*a/b is invariant under association. No ambiguity. a/bc is not.
a/bc or 48/2(9+3) are just <snip>. Nothing more.
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