op amp

Discussion in 'The Projects Forum' started by Jon Stoker, Dec 14, 2013.

1. Jon Stoker Thread Starter New Member

Dec 14, 2013
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0
Given that the precison temperature sensor produces an output voltage (VS: sensor Output Voltage) according to the equation Vs = (12mV) T°C + 1.8V
This equation can be expressed in terms of temperature (T) versus sensor Voltage (Vs).ie T=(Vs - 1.8) / (0.012)

You are to design the amplifier circuit for this sensor using any combination of inverting amplifiers, non-inverting amplifiers, summing amplifiers (No need to use all types of amplifier ) together with a 1V Reference voltage source.

The sensor voltage (Vs) and a 1V reference voltage (Vref) are the two input signal of your circuit. Your designed circuit should produce an output voltage (Vo) to indicate the temperature accordingly to the equation Vo = T/10. (°C/10)

ie. When T=0 °C, Vo= 0V and T=100 °C, Vo = 10V

I need to design a circuit using Op-amp.

2. tshuck Well-Known Member

Oct 18, 2012
3,531
675
So, where is it?

This is your homework, you need to put in some effort.

3. Jon Stoker Thread Starter New Member

Dec 14, 2013
4
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help pls.. the design and theory approach

4. tubeguy Well-Known Member

Nov 3, 2012
1,157
197
" Given that the precison temperature sensor produces an output voltage (VS: sensor Output Voltage) according to the equation Vs = (12mV) T°C + 1.8V
This equation can be expressed in terms of temperature (T) versus sensor Voltage (Vs).ie T=(Vs - 1.8) / (0.012) "

Have you solved this equation to get the voltage output range of the sensor?

5. Dodgydave AAC Fanatic!

Jun 22, 2012
5,150
769
Use an LM35 or LM36 and an op amp to amplify it.

6. Jon Stoker Thread Starter New Member

Dec 14, 2013
4
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so i need to offset the voltage of -1.8v. a summing amplifier is used and also put an inverting stage before the summer.. to change the polarity..

7. Jon Stoker Thread Starter New Member

Dec 14, 2013
4
0
T=(Vs-1.8)/(0.012)
Vo =(Vs-1.8)/0.12= (1/0.12)Vs-(1.8/0.12)Vref