Hi,
I wanted to check some answers for the question that are in the attachement. There are 3 question A,B,C which answers are povided below
A.
Temp change of 24dC
Temp coefficient of input offset = 15uV/dC
\( 24*15*10^{-6} = 0.36V\)
\( gain = \frac{2.2*10^6+10*10^{3}}{10*10^{3}} = 221\)
\(221 *2*10^{-{3}} = 0.442\)
So the variation is
\( 0.442 - 0.36 = 0.082V\)
B.
input offset voltage = 0.69mV
\( voltage gain =\frac{ 1*10^6+10*10^{6}}{10*10^{6}} = 101\)
error voltage at output
\( 101*0.69*10^{-3}= 0.06969V\)
so the error voltage at the output is 0.06969V
C.
Amp gain = 668
Resistor = 32k
input offset current = 7.3nA
\( Vin = IR = 7.3*10^{-9} * 32*10^{3}= 0.0002336V\)
So the error voltage at the output is
\( Voutput = gain * Vin = 668* 0.0002336 = 0.156044V\)
So the error voltage at the output is 156mV
Thanks for your time and help
Kayne
I wanted to check some answers for the question that are in the attachement. There are 3 question A,B,C which answers are povided below
A.
Temp change of 24dC
Temp coefficient of input offset = 15uV/dC
\( 24*15*10^{-6} = 0.36V\)
\( gain = \frac{2.2*10^6+10*10^{3}}{10*10^{3}} = 221\)
\(221 *2*10^{-{3}} = 0.442\)
So the variation is
\( 0.442 - 0.36 = 0.082V\)
B.
input offset voltage = 0.69mV
\( voltage gain =\frac{ 1*10^6+10*10^{6}}{10*10^{6}} = 101\)
error voltage at output
\( 101*0.69*10^{-3}= 0.06969V\)
so the error voltage at the output is 0.06969V
C.
Amp gain = 668
Resistor = 32k
input offset current = 7.3nA
\( Vin = IR = 7.3*10^{-9} * 32*10^{3}= 0.0002336V\)
So the error voltage at the output is
\( Voutput = gain * Vin = 668* 0.0002336 = 0.156044V\)
So the error voltage at the output is 156mV
Thanks for your time and help
Kayne
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