Unfortunately not.Have access to a vector network analyzer? Works like a charm.
This certainly is not a bad thing. Minimal overshoot with no capacitive load would suggest that the amplifier has plenty of phase margin >45°.Thanks for the help with the bandwidth guys, got it sorted. One other question, I want to measure the step response of the op amp. To do this I am inputting a 1Vp-p square wave at a low frequency, but I can't see any overshoot on the ouput?
Its the AD8651 , the graph your talking about is on page 9 of the data sheet. Im working with a gain of 100, so by my calculation the phase margin is approx. 67°?What amplifier are you looking at?
Its the AD8651 , the graph your talking about is on page 9 of the data sheet. Im working with a gain of 100, so by my calculation the phase margin is approx. 67°?
Sorry, I was reading the value of the phase axis where the two intersect, my mistake, thanks. So with so much phase margin whats the best way to measure the step response?A closed loop gain of 100 is 40dB. If you drew in a closed loop curve across 40dB, it would intersect the open loop curve ~600kHz and the phase there is -90°. So you have 90 degress of phase margin.
Beautiful, textbook curve IMO.
The way you are doing it is fine. Voltage follower, 1kHz square wave. You can do small signal step response, <500mVp, and large signal step response, >1Vp to observe the overshoot and ringing.Sorry, I was reading the value of the phase axis where the two intersect, my mistake, thanks. So with so much phase margin whats the best way to measure the step response?
by Aaron Carman
by Aaron Carman
by Duane Benson
by Robert Keim