# Notron Theorem

Discussion in 'Homework Help' started by Apolonio de Tyana, Jun 13, 2004.

Jun 12, 2004
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2. ### Mjollnir Member

Apr 22, 2004
27
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left side

VOC = voltage across the 4kohm resistor in parallel (which is in series in the 4kohm resistor next to the source) = 4 / (4+4) * 10 = 5V

total current delivered by 10V source when short circuited = 10 / (4K + 4K||3K) = 1.75mA

ISC = 4/(3+4) * 1.75mA = 1mA

so RTH = 5kohm, ur norton equivalent for the lefthand side is a 1ma current source with a 5 kohm resistor in parallel..

right hand side

do the exact same thing, but with 2 sources u can use either superposition or node voltage analysis...

3. ### Apolonio de Tyana Thread Starter New Member

Jun 12, 2004
3
0
Please, would you try to explane me again? Why you have used "4 / (4+4) * 10"?

4. ### Mjollnir Member

Apr 22, 2004
27
0
when it's open circuit, no current flows tru the 3k resistor, hence the voltage across A and B is the same as the voltage across the 4K resistor in parallel..

but the 4k resistors are in series with voltage source when open circuit, so just use voltage division...