Norton's theorem

Discussion in 'General Electronics Chat' started by Dritech, Dec 8, 2012.

1. Dritech Thread Starter Well-Known Member

Sep 21, 2011
756
5
Hi,

Is Isc of the attached circuit 2.124-j8584 ??

I am working using the current devider rule I=(I*Rtot)/(R1+Rtot)

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2. Dritech Thread Starter Well-Known Member

Sep 21, 2011
756
5
Which is the correct current divider rule please:

1) I=(I*Rtot)/(R1+Rtot)

OR

2) I=(Rtot/(R1+Rtot))*I

????

3. kubeek AAC Fanatic!

Sep 20, 2005
4,689
806
You should learn how to math, the two equations are the same. And it should be I1=(Rtot/(R1+Rtot))*I2

4. kubeek AAC Fanatic!

Sep 20, 2005
4,689
806
There is no Isc in that picture. If you mean the current through the 3 ohm resistor, that depends on what is connected between A and B, doesn´t it.

5. Dritech Thread Starter Well-Known Member

Sep 21, 2011
756
5
And what would be the current through the 3 ohms resistor is there is a wire between A and B ?

6. WBahn Moderator

Mar 31, 2012
18,087
4,917
1) These two equations are the same.

2) Neither of them is correct.

First off, you only have one variable for the current, namely I, and it cancels out, your equation is only correct if R1 is identically zero.

But even allowing for the probability that you mean total current on the RHS and one of the branch currents on the LHS, it is still incorrect.

What due you mean by Rtot? Normally, this means the effective resistance. Since they are in parallel, this owuld be

Ztot = (Z1)(Z2)/(Z1+Z2)

Note that you should be using Z and not R because you are dealing with complex impedance and not just simple resistance.

You shouldn't have to rely on memorizing a bunch of formulas. You should be able to derive each and every one of them.

Let's say you want to know I1 and you know Itot, Z1, and Z2. You do not know I2 or Vtot.

Q1) What is Vtot in terms of I1 and Z1?

Q2) What is Vtot in terms of I2 and Z2?

Q3) From Q1 and Q2, what is I1 in terms of the other three quantities?

Q4) What is I2 in terms of Itot and I1?

Q5) Using Q3 and Q4, eliminate I2 and solve for I1, which should now be in terms of the three knowns.