Non inverting op amp

Discussion in 'Homework Help' started by NaveedLatif1, Oct 25, 2014.

  1. NaveedLatif1

    Thread Starter New Member

    Oct 25, 2014
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    Hi, i'm really stuck on my course work. Just wondering if anyone can help me, it would be great! Basically I have to design a non inverting op amp on Multisim, the figures i was given were:

    A = 4
    B = 3
    C = 10
    D = 4 (if i have an even number it means i have to design a non inverting op amp and if i have a odd number a inverting op amp, in my case its a non inverting op amp)
    E = 10 (this is the gain)
    F = 8 Kilo-ohms (this is the input impedance)

    My expected circuit transfer function should be =
    Vout = [-(A x Va) - (C x Vb) + (D x Vc)] x (DE)

    Va, Vb & Vc are my input voltages within a range of 0 to 100mV and determine the output voltage of the amplifier circuit.

    I have only two weeks left until deadline and i have no clue what i am doing, can someone just please help me finish this task, it'll be much appreciated.



     
  2. shteii01

    AAC Fanatic!

    Feb 19, 2010
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    The output is pretty easy.
    Output=Gain(Input)

    Your inputs are:
    Va=0
    Vb=50 mV
    Vc=100 mV

    Your outputs are:
    V1=10Va=10(0)=0
    V2=10Vb=10(50 mV)=500 mV
    V3=10Vc=10(100 mV)=1000 mV

    See? Piece of cake.
     
  3. NaveedLatif1

    Thread Starter New Member

    Oct 25, 2014
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  4. shteii01

    AAC Fanatic!

    Feb 19, 2010
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    Are you doing Summer or Summing Amplifier? Is that why you have 3 inputs?
     
    Last edited: Oct 25, 2014
  5. NaveedLatif1

    Thread Starter New Member

    Oct 25, 2014
    3
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    A summing amplifier
     
  6. shteii01

    AAC Fanatic!

    Feb 19, 2010
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