# Non inverting op amp

Discussion in 'Homework Help' started by NaveedLatif1, Oct 25, 2014.

1. ### NaveedLatif1 Thread Starter New Member

Oct 25, 2014
3
0
Hi, i'm really stuck on my course work. Just wondering if anyone can help me, it would be great! Basically I have to design a non inverting op amp on Multisim, the figures i was given were:

A = 4
B = 3
C = 10
D = 4 (if i have an even number it means i have to design a non inverting op amp and if i have a odd number a inverting op amp, in my case its a non inverting op amp)
E = 10 (this is the gain)
F = 8 Kilo-ohms (this is the input impedance)

My expected circuit transfer function should be =
Vout = [-(A x Va) - (C x Vb) + (D x Vc)] x (DE)

Va, Vb & Vc are my input voltages within a range of 0 to 100mV and determine the output voltage of the amplifier circuit.

I have only two weeks left until deadline and i have no clue what i am doing, can someone just please help me finish this task, it'll be much appreciated.

2. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,297
482
The output is pretty easy.
Output=Gain(Input)

Your inputs are:
Va=0
Vb=50 mV
Vc=100 mV

Your outputs are:
V1=10Va=10(0)=0
V2=10Vb=10(50 mV)=500 mV
V3=10Vc=10(100 mV)=1000 mV

See? Piece of cake.

Oct 25, 2014
3
0

4. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,297
482
Are you doing Summer or Summing Amplifier? Is that why you have 3 inputs?

Last edited: Oct 25, 2014
5. ### NaveedLatif1 Thread Starter New Member

Oct 25, 2014
3
0
A summing amplifier

Feb 19, 2010
3,297
482