Node eqs help

Discussion in 'Homework Help' started by n_adam, Apr 5, 2014.

  1. n_adam

    Thread Starter New Member

    Mar 1, 2014
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    Hi guys,

    I am having trouble figuring out the right equations for the 4 nodes. Can someone tell me what am I doing wrong?

    This is what I have so far.
     
  2. Jony130

    AAC Fanatic!

    Feb 17, 2009
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    I don't see anything wrong with your nodal equation for node 4
    I5 = I6 + 28A
    (V2 - V4)/4 = (V4 - V3)/2 + 28A

    But in your circuit you have 4 node, so to solve this circuit you need only 3 nodal equation. And one of the node you treat as a reference node (GND).
     
  3. n_adam

    Thread Starter New Member

    Mar 1, 2014
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    OK I will try to solve it that way and let you know if I got the right answers.
     
  4. n_adam

    Thread Starter New Member

    Mar 1, 2014
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    OK I tried to solve it using the node under v1 as a reference node but I still can't get the right answer. I simulated the circuit with multisim and v1 should be 60V, v2 86, and v3 13. I am still doing something wrong...
     
  5. Jony130

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    Feb 17, 2009
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    Last edited: Apr 5, 2014
  6. shteii01

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    Feb 19, 2010
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    I have a question about v2. It seems to me that v2 is voltage drop across two resistors.

    I think you are looking at v2 as being voltage drop across 4 Ohm resistor and I think that is wrong. I think v2 is equal to sum of voltage drop across 4 Ohm and v3.
     
  7. shteii01

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    Feb 19, 2010
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  8. n_adam

    Thread Starter New Member

    Mar 1, 2014
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    Oh OK I got it now, thank you guys!
     
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