Nodal Analysis

Discussion in 'Homework Help' started by p75213, Aug 1, 2011.

  1. p75213

    Thread Starter Member

    May 24, 2011
    39
    0
    The answer is 20V but I am having problems figuring out how it is derived. I think there is a supernode in there but the voltage sources in parallel have got me confused.
     
  2. blah2222

    Well-Known Member

    May 3, 2010
    554
    33
    KCL(Vo):

    \frac{Vo - 30}{2k} + \frac{Vo - 20}{5k} + \frac{Vo}{4k} = 0

    Vo(\frac{1}{2} + \frac{1}{5} + \frac{1}{4}) = 19

    Vo(\frac{20 + 8 + 10}{40}) = 19

    Vo(\frac{38}{40}) = 19

    Vo = 20
     
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