Nodal analysis problem

hgmjr

Joined Jan 28, 2005
9,027
If you will post what you have done so far to solve the problem we can help you get past your snag point.

hgmjr
 

The Electrician

Joined Oct 9, 2007
2,970
this could help. its a solutio to the problem. the solution is so quick that i dont see how they found the answer.
I don't see how they get an answer, either. They only have 4 equations, but there are 5 unknowns. The current Is2 doesn't appear in any of their equations, but surely it has an effect on the solution.

Perhaps they got an answer from a solution book.
 

Thread Starter

cheypr

Joined Oct 13, 2009
34
I don't see how they get an answer, either. They only have 4 equations, but there are 5 unknowns. The current Is2 doesn't appear in any of their equations, but surely it has an effect on the solution.

Perhaps they got an answer from a solution book.
thanks, any other idea or suggestion in how to solve this exercise.
 

The Electrician

Joined Oct 9, 2007
2,970
Your equation for SN2 is incorrect.

You have:

-(1/1k)Va + 0Vb + (1/1k+1/1k)Vc + (1/1k)Vd = -.002

You should have:

-(1/1k)Va + 0Vb + 0Vc + (1/1k+1/1k)Vd + (1/1k)Ve = -.002

Then your matrix will be:

Rich (BB code):
[ .0025  -.0005 -.001 ]
[ -.0005  .001    0.  ]
[ -.001    0.    .003 ]
Solving will give you :

Va = .69565
Vb = 4.3478
Ve = 7.5652
 

The Electrician

Joined Oct 9, 2007
2,970
do you have the answers
I got v1 = 4.2 A & v2 = 16.8
and voltage = 33.6
I want to know if I did it right or not
I don't know what you mean by "v1 = 4.2 A"; it looks like you're saying that v1 = 4.2 amps.

And when you say "voltage = 33.6", what voltage are you referring to?

Look at the designators in the .pdf file attached to post #3. Then:

Va = .69565
Vb = 4.3478
Vc = -5.3043
Vd = -4.43478
Ve = 7.5652
 
Top