Needed Formula

Discussion in 'General Electronics Chat' started by KCHARROIS, Dec 18, 2012.

  1. KCHARROIS

    Thread Starter Member

    Jun 29, 2012
    292
    1
    Hello

    I'm in need of a formula that to convert a j value to an inductance or capacitance value.

    Example: How does j126Ω at 100 MHz equal 200nH

    Thanks
     
  2. MrChips

    Moderator

    Oct 2, 2009
    12,421
    3,357
    Z = jωL = j2πfL

    R = 2πfL

    L = R/(2πf)

    R = 126Ω
    π = 3.1416
    f = 100MHz

    For capacitance:

    Z = j/(ωC) = j/(2πfC)
     
    Last edited: Dec 18, 2012
  3. Papabravo

    Expert

    Feb 24, 2006
    10,136
    1,786
    Simple algebra.

    If
    XL = ωL, then L = XL / ω, which also equals XL / (2πf)

    So:

    126 / (2 * 3.1415926 * 100E6) = 200E-9 = 200 nH
     
    #12 likes this.
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