With power applied to the board, what voltage are you getting from the right 2 pins then the left 2 pins?
Common (black) meter probe on ground, meter the left 2 then the right 2.
You should have voltage on all four pins of both devices.
If you have none, that part is not the problem.
If you have voltage on one side and not the other, or only one pin, it is that part.
Opto couplers use a led on one side to shine onto a photocell on the other. This way, the signal gets across the isolation line but there is no conductive path for noise or faults to cross.
If you have voltage on one side, both pins, that means the LED is most likely lighting.
If you have voltage on both sides, that means the LED IS lighting and the photo receiver is working
If you have voltage on both pins on one side put none on the other, that means the LED is burned out or the photocell has failed.
I was trying to look at the board when OP said 115VAC goes to one pin of those, which is like ..never.
Opto's can't take that voltage..well except for galvanic isolation.
Its the common wire that hooks to one of the IC leads, opposed to the hot wire. Reading from hot to the IC leads I get 122, 122, 122, 122, and on the other side(near edge of PCB) I get 118, 118, 116, 122vac.
Reading from gnd to the IC leads I get 0, 0.3, 0.3, 0 and the other side 7.5, 4.7, 7.0, 0.0vac
His tech is wrong giving him wrong results. The OPTO's does not use common ground.
And without a shema or seeing the board I donno where to look at.
He did not show me, thus the quote. measurements are wrong. Me no Guru. Me king as some might say.
I agree that we will not have exact voltages, but If the opto has power on 1 side ,the photorsensor is not receiving, then the opto is bad.
they are pretty inexpensive, so I would replace them.