Need help with this mesh/nodal analysis problem

Discussion in 'Homework Help' started by mesaman000, Jun 29, 2010.

  1. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    So guys. I'm having trouble with this problem..

    I try using nodal analysis but don't know how to treat the voltage sources going into the nodes. So i decided to use mesh analysis and found all Ia, Ib, Ic, and Id.. I got Vo= .3 V but I'm not sure if this is right.. And also I have no idea how you're supposed to approach it using nodal analysis either.

    Firstly can someone verify that the answer is .3 V? Cuz I got the current Ic going through that 1k resistor on the right (which is Vo) is .3 mA , therefore .3*1= .3 V..

    And secondly can someone help me on how I can start this problem using nodal analysis?

    I would REALLY appreciate it. Thanks a lot![​IMG]
     
  2. tskaggs

    New Member

    Jun 17, 2010
    26
    3
    There are three unknowns in this circuit: V_{y},  I_{x}, and V_{0}.

    From examination of the center node you can see that  I_{x} and V_{y} are related by the equation

     I_{x}=\frac{V_{y}-2V}{1k}

    So now you only need two equations to solve the rest of the problem.

    Perform nodal analysis with the supernode (i.e., the node that includes V_{y} and the source 2V_{y}) and the node on the center/right-side (3V_{y}-V_{o}).

    Do you need help writing the equations from this point?
     
  3. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    ermm..well for the supernode i'd have to include the current for the bottom left (we don't know the current going through that 2 v voltage source)
     
  4. tskaggs

    New Member

    Jun 17, 2010
    26
    3
    Actually the 5 currents leaving the supernode correspond to the five resistors. So the supernode equation would be:

    0=\frac{V_{y}}{1k}+\frac{V_{y}-2}{1k}+\frac{3V_{y}-2}{1k}+\frac{3V_{y}-(3V_{y}-V_{0})}{1k}+\frac{V_{y}-(3V_{y}-V_{o})}{1k}

    Maybe that will help you figure out the last equation.
     
  5. mesaman000

    Thread Starter New Member

    Jun 29, 2010
    16
    0
    OH i see..I thought you were including the bottom middle (ground) to your supernode but thats just ground so we already know what that is.. ahh that makes sense. Thanks a lot!!
     
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