need help with math simplification

Discussion in 'Homework Help' started by s3b4k, Mar 11, 2010.

  1. s3b4k

    Thread Starter Member

    Feb 15, 2010
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  2. someonesdad

    Senior Member

    Jul 7, 2009
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    Doesn't look like an equality to me -- plug in n = 1 and k = 0 (if you don't like those numbers, try n = 2 and k = 1).
     
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  3. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    \frac{(n-k)![(n-k+1)(n-k+2)-k(n-k+1)+k^2]}{k!(n-2k+2)!}

    is the closest I can come. Haven't checked it carefully.
     
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Nope that didn't work either ...

    Maybe ...

    \frac{(n-k)![(n-k+1)(n-k+2)-k(n-2k+1)-k^2]}{k!(n-2k+2)!}

    What's the point of the problem anyway?
     
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  5. s3b4k

    Thread Starter Member

    Feb 15, 2010
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    because i needed to proove this identity and it was not equaling for me, just wanted to see if it would work for anyone else to see if I was making a math error
     
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