Question: Calculate the dc voltage at the collector of Q1 if the capacitor C3 becomes shorted.
Attempt:
Assuming a stiff voltage divider at the base of Q1 I get VE1=10k*10/(10K+47k) - 0.7 = 1.05v. Therefore IE1 = 1.05mA. If I assume that the dc collector and emitter currents for Q1 are roughly the same, then I think we have this situation:
Applying KCL at node VC1 and doing the maths yields VC1=3.77v.
Could someone tell me if this is a correct method of solving the problem? The solutions manual I found for the book does it in some weird way which doesn't make sense to me, and gets a different answer too
Thanks!
Jon.
Attempt:
Assuming a stiff voltage divider at the base of Q1 I get VE1=10k*10/(10K+47k) - 0.7 = 1.05v. Therefore IE1 = 1.05mA. If I assume that the dc collector and emitter currents for Q1 are roughly the same, then I think we have this situation:
Applying KCL at node VC1 and doing the maths yields VC1=3.77v.
Could someone tell me if this is a correct method of solving the problem? The solutions manual I found for the book does it in some weird way which doesn't make sense to me, and gets a different answer too
Thanks!
Jon.
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