First question is about this:

http://img14.imageshack.us/img14/8672/13249405.jpg

I'm only concerned with part a... no need for the truth table, I guess my question is regarding equation manipulation

The equation I get, which was marked right for me was
Z = NOT(A + (NOT(A)*B) + (B*C))

Kind of hard to see from that, but its A + AB + BC with a line over the whole thing to not it, as well as a small not line over just the A in the AB term.

However in the back of the book it is Z = NOT(A+B) which comes up with the same outputs as my equation in the truth table.

Apparently some simplification was done using Demorgan's Theorem or something so I was wondering if someone could easily spot how to simplify it

Second question
I forgot how to do the following problem

http://img14.imageshack.us/img14/8229/84474254.jpg

I remember it has something to do with N amount of resistors in parallel R/N is the equivalent R, so as N goes to infinity the effective (total) resistance goes to 0.. and this is contradictory to what I might have thought, i.e. more resistors = more power consumed... so in this case more resistors = less power consumed? somethin' like that

 

Homework problems...

The answer is probably in the text.

 

Actually they aren't, and even if they were... the book still doesn't explain things even half as well as the people on this forum

 

For the first question

(A + A'B + BC)' = A'.(A'B)'.(BC)' -Demorgan's law

= A'.(A+B').(B'+C')

= A'B' (B'+C') [A'A is 0]

=A'B'+A'B'C'

= A'B'(1+C') [1+C'=1]

Z =A'B' = (A+B)'

For the second question i think the equivalent of ON-state resistance of the Mosfets should equal R and hence maximum power is (Vs²/4 R) .Iam not sure though,lets wait together for some conformation

 

Thanks vvkannan,

Your Boolean Algebra makes sense...

 

In the second problem, the minimum value of load resistance on Vss (maximum current) occurs when all inputs are high. Assuming R is internal to the gate, this is then the condition for maximum dissipation. You should be able to calculate dissipation as a function of R, Ron, and n. Come back with your answer and we can critique it.

EDIT: If R is not internal to the gate, then the answer will be different.

 

I'm still pretty lost..

1) If my set of inputs are all 1, i.e. all the resistors in parallel are on:

Rtotal = Ron/N where N -> infinity Ron -> 0 so I only have R

2) If I have them all off, no current flows correct?

I think maybe a fundamental example would help, this is one of my weaker areas (as if the others already aren't weak)

 

I'm still pretty lost..

1) If my set of inputs are all 1, i.e. all the resistors in parallel are on:

Rtotal = Ron/N where N -> infinity Ron -> 0 so I only have R

2) If I have them all off, no current flows correct?

I think maybe a fundamental example would help, this is one of my weaker areas (as if the others already aren't weak)

Remember the power formula P=V^2/Rt in the general case.

In your case, V is constant and unchangable and equal to Vs, so maximum power will occur when the resistance is minimum.

Rt=R+Ron/N

Obviously Rt gets smaller as N gets larger.

 

Thank you, this makes sense...

 

Sorry ihaveaquestion,I thought we need to find the maximum power absorbed by the Mosfets and hence applied max.power transfer theorem.steveb's reply cleared it up.

 

No problem vvkannan, I appreciate your input