More PF problems. Answer check.

Discussion in 'Homework Help' started by matt_t, Aug 21, 2012.

  1. matt_t

    Thread Starter Member

    Aug 18, 2012
    30
    0
    I have the following question:

    An industrial shop has a load of 10 KVA at a power factor of 0.34 lagging. A 5.0 KVAR capacitor is installed for power factor correction purposes. The new overall power factor of the shop would be:


    I start off by drawing a power triangle with the angle -cos 0.34= 70.12 deg and Apparent Power of 10,000VA

    From this I work out true power = 10000 x cos 70.12 = 3400W
    Reactive Power = 10000 x sin 70.12 = 9404VAR

    A 5000VAR Capacitor is added to the circuit. Which = 9404VAR - 5000VAR = 4404VAR.

    New Apparent power= √3400²+4404² = 5563.7VAR

    PF= TP/AP = 3400W/5563.7VAR = 0.611

    Is this correct?
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    Yes - correct.
     
    matt_t likes this.
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