Mesh Current Analysis for an RLC Circuit - Help!

Discussion in 'Homework Help' started by mdb, Feb 11, 2011.

  1. mdb

    Thread Starter New Member

    Feb 11, 2011
    3
    0
    Hello,

    The assignment says find the magnitude and phase of V0 using mesh current analysis. I simulated the circuit and found the value of V0 to be 7.591 <72.0° V. However, I wasn't able to solve using mesh current method because of the current source in the middle.

    The circuit diagram is attached. Any help is greatly appreciated. Thanks.
     
  2. lezahyoj

    New Member

    Feb 7, 2011
    11
    0
    For two meshes containing the same current source take a path around the outside of the two meshes avoiding the current source - this is called a super mesh.
     
  3. mdb

    Thread Starter New Member

    Feb 11, 2011
    3
    0
    Thank you so much. Here is what I have so far. The final answer is different from what I had in PSPICE! Can someone please confirm my solution?
     
  4. The Electrician

    AAC Fanatic!

    Oct 9, 2007
    2,284
    328
    I get Ic = 8.538 + j3.081

    I think you have a wrong sign for the (1,4) element of your matrix.
     
  5. mdb

    Thread Starter New Member

    Feb 11, 2011
    3
    0
    Thanks alot! I made the correction and got the same number Ic = 8.538 + j3.081.
     
    Last edited: Feb 12, 2011
  6. lezahyoj

    New Member

    Feb 7, 2011
    11
    0
    but that wasn't the same as the result of your PSPICE right?
    I know a different procedure from yours.

    you obtained an equation IC-IB=12, from that you will get IB=IC-12. Try to substitute this equation from the other equation you get from the loops then omit the [0 -1 1 0 12] from the matrix.

    I'm not quite sure if this will work but there's no harm in trying (if no high voltage is involved) :D
     
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